Question

A block of mass 5 kg is placed on table and it is pressd by 10N than normal force exerted by table on book ?​

Answer 1

Explanation:

Mass of book=5kg

Then force exerted by earth on book= mg=5×9.8=49 N

External force exerted on book = 10

By Newton's third law of motion we get,

Force exerted by table on book= mg+10=49+10=59N

Hence force exerted by table on book = 59 N

Answer 2

Answer:

REFER TO ATTACHMENT FOR ANSWER !

Total Force = 59N

❣️ Regards KarnShubham ❣️