Physics, asked by mahashanu01, 4 months ago

A block of mass 5 kg is present on a plank of mass 10 kg. The coefficient of friction
between them is 0.8 and that between plank and the ground is 0.4. If the plank is
being pulled with a constant force 90 N to the right, find their accelerations.​

Answers

Answered by susmitasenb8468
0

Answer:

sorry I don't know the answer is

Explanation:

SO much more than just yyyuuuuuu brilliant

Answered by mad210203
1

Given:

Mass = 5 kg

Plank mass = 10 kg

Friction between block and plank = 0.8

Friction between plank and ground = 0.4

Force = 90 N

To find:

We need to find the acceleration.

Solution:

Acceleration is that the rate of amendment of rate. Usually, acceleration suggests that the speed is dynamic, however not continuously. once an object moves in an exceedingly circular path at a continuing speed, it's still fast, as a result of the direction of its rate is dynamic.

& F=ma \\  \\  & a=\frac{F}{m} \\ \\

So,

a=\frac{90}{15}=6\text{ m}{{\text{s}}^{2}}

Maximum possible acceleration of 5kg block.

& {{a}_{1}}=\frac{FrictionForce}{mass} \\  &  \\  & {{a}_{1}}=\frac{90}{5} \\  &  \\  & {{a}_{1}}=18\text{ }m{{s}^{2}} \\

Therefore, the acceleration is \[6m{{s}^{2}}\] and \[18m{{s}^{2}}\].

Attachments:
Similar questions