Question

A block of mass 5 kg is pulled on a frictionless floor by a force of 210 N directed at 30° to the
horizontal if the block moves 3.0m find the work done by the force:
A. 21513N B. 315/3 N C.415/3N
D. 11573 N

Answer 1

Answer:

315√3

Explanation:

w=f×d×cos angle

w=210×3×cos 30

w=630×√3/2=315√3

Answer 2

Answer:

315underoot 3J

Explanation:

GIVEN DATA:

mass of block=5kg

force=210N

displacement=3.0m

angle=30degree

TO FIND:

work done =force. displacement

as work is scalar quantity so,  

in place of dot ,we put cos angle .now

w=fdcos angle

put values:

w=210.3cos 30

as cos 30 is= underoot3/2 or 0.866 so

w=630* underoot3/2

now after solve answer is

315underoot3J

it will be helpfull for u.