a block of mass 5 kg is slipping down a rough inclined wedge of mass 15kg kept at rest on horizontal surface with constant velocity and the inclined angle is 30°
Answers
Answered by
2
Answer:
what do u want me to find???
if you need force
force is 50sin30° which means
25N
and if you need friction
F = ma
25N - FR =5×0
25N = FR
Attachments:
Similar questions