Question

A block of mass 5 kg slides down an incline of inclination 30 and lenghrh 10m find work done by gravity

Answer 1

Answer:

Explanation:

F = ma

θ = 30°

a = gsinθ

a = g × 1 / 2

a = 4.9 m/s²

W = Fs

W = mas

W = 5 × 4.9 × 10

W = 5 × 49

W = 245J

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Answer 2

Solution :-

Here we've been provided with the mass of block which is of 5kg and is sliding down from the top. The thing at which it is slipping is a triangular object whose inclination is of 30°.

• Mass (m) = 5kg
• Length= 10m

As we know that work done is calculated by the formula :

• W.D. = F.S.

Here,

• F is force exerted
• S is displacement

However force exerted is the gravitational force exerted by the earth in downward direction.

Therefore,

• W.D. = mgh

Lets find out height !!

• h = 10 × sin 30°
• h = 10 × (1/2)
• h = 5 × 1
• h = 5m

Lets substitute the values in the formula!

>> W.D. = 5 × 9.8 × 5

>> W.D. = 25 × 9.8

>> W.D. = (25 × 98) / 10

>> W.D. = (5 × 98) / 2

>> W.D. = 5 × 49

>> W.D. = 245 J