Question

a block of mass 50 kg slides over a horizontal distance of 1 metre if the coefficient of friction between then surfaces is 0.2 then work done against friction is​

Answer 1

Answer:

• frictional force =0.2
• $0.2 \times 50 \times 10 = 100$
• $work \: done \: against \: friction \: = f orce \times displcemnt$
• $w = 100 \times 1 = 100j$

Answer 2

Answer:

98.1 Joules

Explanation:

m = Mass = 50 kg

$\mu$ = Coefficient of friction = 0.2

g = Acceleration due to gravity = 9.81 m/s²

s = Dislpacement = 1 m

$F_f=\mu mg\\\Rightarrow F_f=0.2\times 50\times 9.81\\\Rightarrow F_f=98.1\ N$

Frictional force = 98.1 N

$W=F\times s\\\Rightarrow W=98.1\times 1\\\Rightarrow W=98.1\ J$

Work done against friction is 98.1 Joules.