Question

A block of mass 500 g slides down on a rough incline plane of inclination 53° with a uniform
Find the work done against the friction as the block slides through 2 m. (g = 10 m/s?]
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Answer 1

Answer:

W= rxF

= 2m x mg sin53

= 2x 0.5x10x 4/5 = 8J

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Answer 2

Answer:7.98 J

Step-by-step explanation:

Mass of block=500 gm

inclination$=53 ^{\circ}$

Block slides with uniform velocity i.e. net force is zero on block

Friction force=mg\sin \theta [/tex]

$f_r=mg\sin \theta$

$f_r=0.5\times 10\times \sin (53)=3.99 N$

work done $=f\cdot x$

Work done $=3.99\times 2=7.98 J$