A block of mass 500g is pulled from rest on a horizontal frictionless bench by a steady force F and travels 8m in 2s find
A. acceleration
B. the value of F
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KIO
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Initial velocity = zero
Mass of block = 500g
Applied force = F
Distance travelled in 2s = 8 m
- Acceleration
- Value of applied force
❖ Assuming that body has constant acceleration throughout the motion..
Acceleration of block can be easily calculated by applying equation of kinematics.
Second equation of kinematics :
- d = ut + 1/2 at²
» d denotes distance
» u denotes initial velocity
» t denotes time
» a denotes acceleration
By substituting the given values;
➙ d = ut + 1/2 at²
➙ 8 = (0 × 2) + 1/2 a (2)²
➙ 8 = 0 + 4a/2
➙ 8 = 2a
➙ a = 8/2
➙ a = 4 m/s²
♦ As per newton's second law of motion, force is measured as the product of mass and acceleration.
Mathematically, F = m a
[Mass (m) = 500g = 0.5kg]
➙ F = 0.5 × 4
➙ F = 2 N
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