Question

A block of mass 50kg slides over a horizontal distance of 1m. if the coefficient of friction between their surfaces is 0.2, then work done against friction is
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Answer 1

work done= 50×0.2

work done= 10 J

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Answer 2

Answer:

Work done = F X S

$5 0 \times 0.2 = 10$

$w = 10j$

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