Question

A block of mass 5kg is lying on a frictionless table. A force of 20N is applied on it for 10seconds. Calculate its KE.

Answer 1

Hi dear !!!

mass = 5 kg


force = 20 N


f= ma

20N = 5× a

a = 4 m / s²

time = 10s

V = u + at


0 = u + 40


u = -40 m / s





so KE of the body is

1/2 m v²


=> 1/2 × 5 × 40× 40


4000 j



hope it help you dear !!!

thanks

Answer 2

Answer:

mass,m = 5kg

force , f = 20 N

F=M*A

20= 5×a

a= 20/5m/s^2

=4m/s^2

Time, t= 10s

v=u + at 0=u+4×10

0=u+40

u= (-40m/s)

So, KE of body is 1/2 mv^2

=1/2×5×40×40

=100×40

=4000J

or

=4KJ

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