Question

A block of mass 5kg is lying on rough horizontal surface.The coefficient of static friction and kinetic friction is 0.3and0.1 and g=10m/s².The frictional force on the block is
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Answer 1

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• Given :

=> block of 5 kg is lying on rough horizontal surface.

=> co-efficient of static and kinetic friction are respectively 0.3 and 0.1

=> gravitational acceleration = 10m/s^2

• To Find :

=> The frictional force acting on the block

• Concept :

=> Block is at rest position so only static friction will act

=> Normal reaction = weight force

• Formula :

=> formula of static friction is given by

$\boxed{ \sf{ \pink{f = (\mu)s \times n = (\mu) \times mg}}}$

• Formula :

=> f = 0.3×5×10 = 15N

=> f = 15 N