A block of mass 5kg is moving in the x-direction with a constant speed of 20 M/sec. it is subjected to a retarding force F=-0.2x j/m during it's travel from x=30mtox=40m.find the final kinetic energy.
Answers
Answer:
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Concept:
- Forces
- One dimensional motion
- Conservation of energy
Given:
- mass of block = 5 kg
- constant speed v = 20 m/s
- Force = -0.2 N
- Displacement ds= 40 m - 30 m = 10 m
Find:
- The final kinetic energy
Solution:
First, we need to calculate the initial kinetic energy.
KE = 1/2mv^2
KE = 1/2(5)(20)^2
KE = 1000J
Work done by the retarding force is the product of the force and the displacement.
WD = F*ds
WD = integral product of the force and displacement
WD = 0.1(40^2-30^2)/2
WD = 35 J
Final KE = Initial KE - work done
Final KE = 1000-35 = 965 J
The final kinetic energy is 965 J
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