A block of mass 5kg is moving with a velocity of 36 km/hr.If its velocity is reduced to 18km/hr in 0.5 sec.What is the retarding force on the block
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Given data:
Mass=m= 5 kg
initial velocity=Vi=36 km/h = 10 m/s
final velocity=Vf= 18 km/h = 5 m/s
time=t=0.5 sec
To find:
retarding force= F = - ma
, acceleration=a= ?
Solution:
For acceleration,
acceleration = a = Vf - Vi / t = (5 - 10) / 0.5 = (-5) / 0.5 = - 10
Now,
retarding force = F = -(5)(-10) = 50 N
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