a block of mass 5kg is suspended by means of a uniform cord of mass 2kg attached to the root of a lift. if the lift starts accelerating up with a=5mJ^-2. The tension at the mid point of the cord is
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Explanation:
with the rope as a system F.B.D. of whole system.
F0−100=10×2 ......... (i)
F = 120 N
According to Newton's second law, net force on rope.
F = ma = (2)(2)
= 4 N ......(ii)
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