Question

A block of mass 5kg is suspended by means of a uniform cord of mass 2kg attached to the roofof a lift as shown. If the lift starts accelerating up with a = 5 m/s2 (g = 10 m/s2). The tension in themidpoint of the cord is​

Answer 1

Answer:

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Explanation:

Answer 2

Answer:

The tension in the midpoint of the cord is​ 90N

Explanation:

Tension is the opposite of compression force. All the objects that are present in contact with each other exert a force on each other. The best example of a tension force can be seen while pulling a rope. When a pull force is applied to the rope, a significant amount of tension gets built.

total mass m= mass of cord +block of mass

                    =1 kg +5 kg=6 kg

relative acceleration =a+g

                                   =5 m/s²+10 m/s²

                                    =15 m/s²

tension at mid point of cord T = m(a+g)

                                                   =  6 kg x 15 m/s²

                                              T=90N

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