Question

a block of mass 5kg is suspended from the end of a vertical spring which is a stretched by 10cm under the load of the block . the block is given sharp impulse from below so that it acquire an upward speed of 2m/s how high will it rise .take g=10 m/s
​

Answer 1

Answer:

Mass of the block = 5 kg.

v = 2m/sec.

Now Kinetic energy of the block is (1/2) mv².

Assume the new height of the block be h.

So the change in potential energy at the highest point is equal to Kinetic energy.

∴mgh=(1/2)mv²

 

h=(1/2g)v²

 

h=22 /(2×10)

h=1/5

 

h=0.2 m

or h=20 cm.

It will rise upto 20 cm.

Explanation:

please mark as BRAILIEST and thankx the answer