a block of mass .5kg on horizontal table .What steady force is required to give the block of velocity of 2m/s in 4s
Answers
Answered by
0
Here we have
Mass = 5kg
Initial velocity , u = 0 m/s
Final velocity , v = 2m/s
Time , t = 4 s
Acceleration produced in the block , a = v - u / t
= > 2 - 0 / 4
=> 2 / 4
=> 0.5 m/s^2
Force , f = m × a
= 5 × 0.5
= 2.5 N
Therefore , we have to apply a force of 2.5 N to give it a velocity of 2m/s in 4 s
Mass = 5kg
Initial velocity , u = 0 m/s
Final velocity , v = 2m/s
Time , t = 4 s
Acceleration produced in the block , a = v - u / t
= > 2 - 0 / 4
=> 2 / 4
=> 0.5 m/s^2
Force , f = m × a
= 5 × 0.5
= 2.5 N
Therefore , we have to apply a force of 2.5 N to give it a velocity of 2m/s in 4 s
Similar questions