A block of mass 5kg starts to slide down a frictionless plane having an inclination of 25 from rest at the top the length of the incline is 2m find the acceleration
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Answer:
horizontal components of Fcos65° = ma
i.e sin(90°- 65°)= cos65°
mgcos65° = ma
gcos65° = a
a = 10×0.42
cos 65°=0.42
a= 4.2m/s2
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