a block of mass 5kg was at rest on horizontal frictionless surface .if it is pushed with a force of magnitude 60N
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Answered by
1
Answer:
70 j
Step-by-step explanation:
W.D force +W.D friction =ΔK.E
60×2−25×2=KE
120-50=KE=70
final KE
final =70 J
Answered by
0
Answer:
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