Question

A block of mass 6 kg kept on a horizontal smooth surface is acted upon by a
horizontal force of 48N.
(a) weight of the block acts on ............(the block/horizontal surface)
(b) Draw the free body diagram of the block.
(e) Find the magnitude and direction of acceleration of the block.
(d) What is the force applied by the block on the surface and in which direction.
(e) what is the reaction force for the weight of the block.
(What is the reaction for the force applied by the block on the surface​

Answer 1

Answer:

a) horizontal surface

b)

-------> Block(6kg)

48N

c) F = ma

48 = 6a

8m/s² =a

in the direction of force applied

d) force applied by block on the surface is equal to m x g = 6 x 9.8 = 58.8 in the downward direction

e) the ground applies an equal force in magnitude and a opposite force in direction

hope it helps