Question

A block of mass is pushed at a constant speed along a rough horizontal floor by a constant force 94 N at an angle of 63° above the horizontal. What is the magnitude of the friction force?​

Answer 1

Explanation:

$f = ma \\ constant \: speed \: means \: \\ acceleration \: is \: 0 \\ \\ f = ma \\ f - fr = m \times 0 \\ f = fr \\ 94 \cos(63) = fr$