Question

A block of mass m = 0.5 kg, attached to a
spring with the spring constant k = 450 N/m,
undergoes simple harmonic motion in the
horizontal plane. What is the frequency of the
motion?​

Answer 1

Answer:

The frequency of oscillation is ω=

k/m

The maximum acceleration during SHM is −ω

2

×x

where x is the maximum depression of the spring.

To maintain contact with spring, the maximum SHM acceleration should be equal to acceleration due to gravity, i.e., −ω

2

x=−g⇒x=mg/k=0.5×10/500=1 cm