Question

A block of mass m = 1.62 kg slides down a frictionless incline. The block
is released a height h = 3.91 m above the bottom of the loop.
friction coefficient =0.2
(a) Find the work done by the gravitational force from the top to A,
Wgra ?
(b) Find the work done by the friction force from the top to A, Wfric ?
(c) Find the relation between Wfric and the energy of the object ?

Answer 1

Answer:

The energy lost due to friction on an inclined plane is given as

E=Ffricd

The force due to friction is given as

ffric=μkFN

FN=mgcosθ

By substituting the normal force we get

E=μkmgcosθ⋅d

This is the energy lost is lifting up the mass.

Since the mass is sliding down the energy is given as

E=μR

E=μmg

Since the acceleration due to gravity is constant it depends on the coefficient of friction.

hope it helps.....mark as brainliest if it helps u:)✌