Question

A block of mass m= 12 Kg is pushed at a constant speed, up an incline plane through a distance of s=4.5m and raised to a height h= 2m. The coefficient of kinetic friction between the block and the incline is 0.41. Calculate the work done by Normal force the external force applied parallel to the incline. gravity the frictional force. 1) S Å​

Answer 1

Answer:

Workdone=force*displacement

Workdone=force*displacementforce=coefficient of kinetic friction between the block and the incline*R(mg)

Workdone=force*displacementforce=coefficient of kinetic friction between the block and the incline*R(mg)f=0.41*(12*9.8)

Workdone=force*displacementforce=coefficient of kinetic friction between the block and the incline*R(mg)f=0.41*(12*9.8)f=48.216

Workdone=force*displacementforce=coefficient of kinetic friction between the block and the incline*R(mg)f=0.41*(12*9.8)f=48.216Workdone=force*displacement

Workdone=force*displacementforce=coefficient of kinetic friction between the block and the incline*R(mg)f=0.41*(12*9.8)f=48.216Workdone=force*displacementW=48.216*4.5

Workdone=force*displacementforce=coefficient of kinetic friction between the block and the incline*R(mg)f=0.41*(12*9.8)f=48.216Workdone=force*displacementW=48.216*4.5W=216.972Joule