Question

A block of mass m attached to a lower end of vertical spring the spring is hung from a ceiling as and has force constant value k the mass is released from rest in the spring initially unstretched extension produced in the length of the spring will be

Answer 1

Answer:

K = 200 N/m        x = .05 m

Energy stored in spring = 1/2 kx^2 = 1/2 x 200 x .05 ^2 = 0.25 J

m= 0.5 kg

PE stored in spring = KE imparted to object

0.25 J = 1/2 x 0.5 kg x v^2            v = sqrt 1 = 1 m/s

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Explanation:

Answer 2

K = 200 N/m        

x = .05 m

Energy stored in spring = 1/2 kx^2 = 1/2 x 200 x .05 ^2 = 0.25 J

m= 0.5 kg

PE stored in spring = KE imparted to object

0.25 J = 1/2 x 0.5 kg x v^2          

 v = sqrt 1 = 1 m/s