Question

A block of mass m is attached to a massless spring of spring constant k. The other end is fixed form the wall of a trolley. Initially the spring is unstreched and trolley starts moving with a constant acceleration of 3/4 m/s2. The energy of oscillation as seen from the trolley .

Answer 1

Answer:

pp

Explanation:

Answer 2

Given.

Block of mass m attached to massless spring

of force constant k

Accelaration = 3/4 m/s^-2

To find-

- Energy of oscillation

Solution-

We know that mean position velocity is

maximum

mean Vel= max =WA

(K.E)mean = T.E (P.E=0)

mao

T.E = 1/2 (ma)^2/k

energy of oscillation = 1/2m^9/16 k^-1