A block of mass m is attached to two spring of spring constant k, and k, as shown in figure. The block
is displaced by x towards right and released. The velocity of the block when it is at x/2 will be :
(refer the attachment for figure and options )
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Answer:simply use the fact athat mechanical energy is conserved when conservative forces act.
So, initial elastic potential energy = 0.5*k1*x*x + 0.5*k2*x*x
At x/2 , elastic potential energy = 0.5*k1*x*x/4 + 0.5*k2*x*x/4
So, initial elastic potential energy = Final potential energy + kinetic energy
Use this to find the answer
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