Question

a block of mass m is connected to another block M by a string(massless) . The blocks are kept on smooth horizontal plane.Initially the blocks are at rest. Then a constant force F starts acting on the block of mass M to pull it . Find the force on the block of mass m​

Answer 1

Explanation:

Option 1) \frac{MF}{\left ( m+M \right )} Option 2) \frac{mF}{M} Option 3) \frac{\left ( M+m \right )F}{m} Option 4) \frac{mF}{(m+M)}

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P prateek

Answered

As we learnt in

When 2 Blocks are in Contact -

F-f=m_{1}a

f=m_{2}a

- wherein

a=\frac{F}{m_{1}+m_{2}}

f=\frac{m_{2}F}{m_{1}+m_{2}}

: Acceleration \: of\: the\: system\: a= \frac{F}{m+M}

Force \: on \: block\: of \: mass\: m= ma= \frac{mF}{m+M}

Correct option is 4.

Option 1)

\frac{MF}{\left ( m+M \right )}

This is an incorrect option.

Option 2)

\frac{mF}{M}

This is an incorrect option.

Option 3)

\frac{\left ( M+m \right )F}{m}