Question

a block of mass m is connected to another block of mass small M by a spring (mass less) of spring constant K.The blocks are kept on a smooth horizontal plane initially the blocks are at rest and the spring is unstretched then a constant force F starts acting on the block of mass M to pull it .Find the force on the block of mass capital m​

Answer 1

SOLUTION.

Total mass of the system = M + m

Force acting = F

ACC to NLM.

F = mass of the system × Acceleration

F = (M + m) × a

Acceleration = F/(M+m)

After certain time Spring expands and attain a constant expension at that time it Balance all the force acting on the Block.

For mass m.

Force in right direction = Kx

ACC to NLM

kx = ma

kx = mF/(M+m)

Expansion = mF/k(M+m)

For mass M

Force acting left side = kx

Force acting right side = F

ACC to NLM

Force acting is F - kx

Force = F - k[mF/k(M+m)]

Force = F - mF/(M+m)

Force = (F/M+m) (M+m-m)

Force = FM/M+m

#answerwithquality.

#BAL.