Question

A block of mass m is lying on an inclined plane of inclination theta The coefficient of friction between the
plane and the block is u ( mue) The force required to just move the block up the inclined plane is..??
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Answer 1

Answer:

See the diagram

$N = mgcos \theta \\f = \mu</p><p>N = \mu mgcos \theta</p><p>$

When block is just to move

$f = mgsin \theta \\ \mu \: mgcos \theta = mgsin \theta \\ \mu = \tan( \theta)$