Question

A block of mass m is moving on a rough horizontal surface where coefficient of friction between block and surface is \mu= 0.5. At t = 0 block is moving with a velocity v\overset{\to }{\mathop{v}}\, then a horizontal force f = 2t is applied on it in the direction of velocity. Here t represents time then the speed of block after the application of force-

Answer 1

2t - m*10*0.5= ma
a = (2t - 5m)/m
V = t^2 /m- 5t