A block of mass m is on an inclined plane of angle theta. coefficient of friction between the block and the plane is mu
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If the reaction is N then
Frictional force=u N (u is coefficient of friction).
Since block is placed on the inclined plane, so
N=uN Cos (theta)
Here N and uN both the forces are applied on the block by the inclined plane and both are acting at right angle between them, therefore total force applied on the block by the inclined plane is
F (net)=[(uN)^2+N^2]^(1/2)
If the reaction is N then
Frictional force=u N (u is coefficient of friction).
Since block is placed on the inclined plane, so
N=uN Cos (theta)
Here N and uN both the forces are applied on the block by the inclined plane and both are acting at right angle between them, therefore total force applied on the block by the inclined plane is
F (net)=[(uN)^2+N^2]^(1/2)
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