Question

A block of mass m is placed on a smooth inclined plane of inclination θ with the horizontal. The force exerted by the plane on the block has a magnitude
(a) mg
(b) mg/cosθ
(c) mg cosθ
(d) mg tanθ

Answer 1

The force exerted by the plane on the block has a magnitude mg cosθ

option c is correct

1. Let us assume the angle between inclined plane and horizontal is θ (angle of inclination )
2. The weight of the block is mg
3. Now by resolving the weight component
4. The component of weight perpendicular to the plane is mg cosθ
5. The component of weight along the plane is mg sin θ
6. There is no external force ,so the force is exerted by the block on the plane is mg cosθ
7. And according to the 3rd law of motion action and reaction are equal but in opposite direction .
8. The plane also exert a force mg cosθ but in the opposite direction to the force exerted by the block on the plane

Answer 2

Answer:

Option c

mg cosO

Mark as brainliest answer