a block of mass m is placed on a smooth inclined wedge of inclination theta. the whole system is accelerated
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The complete question is - A block of mass 'm' is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be -
Given:
Block of mass = m
Wedge of incliination = θ.
To Find:
Force exerted by the wedge
Solution:
For an observer on ground, R sinθ = ma and Rcosθ = mg
= a = gtanθ
F = (M+m)a = (M+m)gtan
Now, Force exerted by the wedge on the block -
mg/cos θ or R = mgsecθ
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