Physics, asked by pushkaranand6041, 1 year ago

a block of mass m is placed on a smooth inclined wedge of inclination theta. the whole system is accelerated

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Answered by ZERSTORER
20

Answer:

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Answered by Anonymous
3

The complete question is - A block of mass 'm' is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be​ -

Given:

Block of mass = m

Wedge of incliination = θ.

To Find:

Force exerted by the wedge

Solution:

For an observer on ground, R sinθ = ma and Rcosθ = mg

= a = gtanθ

F = (M+m)a = (M+m)gtan

Now, Force exerted by the wedge on the block -

mg/cos θ or R = mgsecθ

 

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