Question

A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block left ( g is acceleration due to gravity right ) will be:-

Answer 1

Answer:

ho gya yrr bss karo itna hi padho............

Answer 2

Explanation:

Here we should take Pseudo force ( it will be toward the opp side of acceleration)

At eqm

macosθ = mgsinθ

           a = g tanθ

Condition for the block to not slip

Normal should be balanced with he net downward forces

N = mg cosθ + m a sinθ

  =mg cosθ + m g tanθ sinθ

 = mgcosθ + mgsin²θ /cosθ

 =  mg cos²θ + mgsin²θ

                 cosθ

                            N  = mg/ cosθ

                Hope you understand

This is Habel sabu .............Isn't it the Brainliest...............