Question

A block of mass m is placed on a surface with a vertical cross section given by y = x 3 /6 . If the coefficient of friction is 0.5 , the maximum height above the ground at which the block can be placed without slipping is : (a) m/3 (b) m/2 (c) m/6 (d) 2m/3

Answer 1

2 (c)m/6 because frictional force is a force which acts opposite to the applied force

Answer 2

Answer:

Explanation:

Let m be the mass of the block and μ​ be the coefficient of friction. For the sliding plane, we have

 

mgsinθ = μmgcosθ

⇒tanθ = μ

Now, we may write⇒dydx=tanθ=μ=12

We have given, y=x^3/6

∴dy/dx=x^2/2=12⇒x2=1

∴ y=16 m