A block of mass m is placed on a weighing machine and it is also attached to a spring balance. The whole system is placed in a lift as shown in figure. Lift is moving with constant acceleration 10m/s2 in upward direction. The reading of the weighing machine is 500N and the reading of spring balance is 300N. Find the actual mass of the block in kg. Take g=10m/s2.
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Answer:
- 40 kg
Explanation:
Given:
- A block of mass m is placed on a weighing machine and it is also attached to a spring balance.
- The whole system is placed in a lift
- Lift is moving with constant acceleration 10m/s² in upward direction
- The reading of the weighing machine is 500N
- The reading of spring balance is 300N
To Find:
- Mass of the block (in kg)
Solution:
- 'm' be the mass of block
- Let us apply Newton's law on the block (vertical direction)
T + N - mg = ma _______①
- T = 300N
- N = 500N
- a = 10m/s²
⇒ m = T+N / g+a
⇒ m = 500+300 / 20 kg
⇒ m = 800/20 kg
⇒ m = 40 kg
∴ Mass of the block is 40 kg
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