Question

A block of mass m is placed on the floor of an elevator going downwards with some acceleration a.What should be the acceleration a of the elevator so that the block exert force equal to one-fourth of its weight on the surface of the elevator.

Answer 1

weight of block under normal conditions = mg

weight in elevator with acceleration = m(g-a)

now according to question

m(g-a) = 1/4mg

g-a = 1/4g

g- 1/4g = a

a = 3/4 g

or a = 3/4 × 9.8 m/sec sq

((g =9.8 m/sec sq constant))

a = 7.35 m/sec2

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