Question

a block of mass m is placed on the top of a bigger block of mass 2m which is placed on a surface the coefficient of friction between all surfaces is mu =1

Answer 1

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Answer 2

Answer:

Weight of the body = mg.

Let the Horizontal Force be L.

∴ Resultant Force = √(L² + m²g²)

Now, we know that,

 L ≤ friction (because body is not moving)

∴ L = friction = μmg (Maximum)

⇒ F ≤ √(μ²m²g² + m²g²)

∴ F ≤ mg√(μ²+ 1)

Now, This F will make angle θ with the Horizontal which will give FCosθ.

∴ F = mg - F Sinθ

∵ θ should always be less than 90° therefore, it can always be less than 1.

∴ F ≥ mg

∴ Mg ≤ F ≤ Mg√(1+µ2)

Hence, Option (c). is correct.