Question

A block of mass m is pulled along a circular arc by means of a constant horizontal force F as shown. Work done by this force in pulling the block from A to B is.


Explain ​

Answer 1

Explanation:

❤️꧁༒☬☠PRINCE☠︎☬༒꧂❤️

➡️ Work done =Fd, Where d is displacement in direction of F.

⇒Work done=FRsin(60° )

= 23FR $\sqrt[]{} 3 | \\ 2|$

Answer 2

Given: A block of mass m is pulled along a circular arc by means of a constant horizontal force F .

To find: Work done by this force in pulling the block from A to B.

Solution: We consider the displacement that is the direction of force as its the effective component in determining the position of B in x-axis.

The effective displacement is the dotted line between R and B. So, we consider the upper triangle for finding the required work done. Let the distance RB be Sx. Now;

                     sin ∅ = Sx / R

                        Sx = sin ∅ × R  ____(1)

[where, Sx is the displacement in the x-axis]

For work done, we know that:

                       W = F.s

                       W = F. Sx

                       W = F. sin ∅ × R [from (1)]

                       W = FR sin 60°

                       W = √3 FR/ 2

Hence, the work done by this force in pulling the block from A to B is √3 FR/2.