Question

A block of mass ‘M’ is pulled along a horizontal frictionless surface by a rope of mass ‘m’. If a force ‘F’ is applied at the free end of the rope, the net force exerted on the block will be

Answer 1

let T be the tension in the string.

for mass M-

T= Ma

Also considering mass m + M as system-

F =(M+m)a

therefore -

a= F/(M+m)

substituting-

T= FM/(M+m).

this is the force which rope exerts on block.

Answer 2

Answer:-

FM/(m+M)

Explanation_->

Please Refer To The Attachment✔✔

The force experience by the block will be equal to the tension produce in the rope...

Let the acceleration of the system be a

So

Making the FBD of the two bodies(Rope and the Block).....

For Rope [Fig. 2]

F-T= ma

____________________(1)

For Block [Fig. 3]

T=Ma

____________________(2)

Divide (1) By (2)

F-T/T=m/M

FM-MT=mT

So

T= Force by the Block =FM/(M+m)