Question

A block of mass m is released on the top of a
of length x and inclination as shown in figure
rough. If block comes to rest after movina
horizontal surface, then coefficient of frictior
surface is
ed on the top of a smooth inclined plane
shown in figure. Horizontal surface is
o rest after moving a distance d on the
and
ce then coefficient of friction between block
X cos
(2)
20
x sine
(1)
20
x cose
x sine
(3)
D
Akach Tomor
Pin D​

Answer 1

Answer:

Explanation:

"Answer:  xsin(theta)/d

Explanation:

As per the question, we get to know that the Mechanical energy is conserved

To solve the question, we have the following  information given in the question

u=0, v=0

mgh-(M)mgd=Kf - Ki

            =(1/2)mv² -(1/2)mu²

             =0

So, mgh=Mmgd

      M=h/d......        

We also know that :

h=xsin(theta)

Thus, M=xsin(theta)/d

In the above equation, we know that  M=co-efficient of friction

"