a block of mass m is released on the top smooth inclined plane of length x nd inclination theta. horizontal surface is rough. if block comes to rest after moving a distance d on the horizontal surface then coefficient of friction between block and surface is
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Mechanical energy is conserved
u=0, v=0
mgh-(M)mgd=Kf - Ki
=(1/2)mv² -(1/2)mu²
=0
So, mgh=Mmgd
M=h/d...... But, we know that h=xsin(theta)
Thus, M=xsin(theta)/d
Where, M=co-efficient of friction
Explanation:
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