A block of mass m is stationary on a rough inclined plane making an angel with the horizontal. Find the contact force between block and the plane
Answers
contact force between the block and plane is mg.
see figure, a block of mass m is stationary on a rough inclined plane making an angle θ with horizontal.
component of weight along plane = mgsinθ
component of weight perpendicular to plane = mgcosθ
so, contact force between the block and plane, N = mgsinθ i + mgcosθ j
magnitude of contact force , |N| = √{(mgsinθ)² + (mgcosθ)²}
= √{m²g²sin²θ + m²g²cos²θ}
= √{m²g²(sin²θ + cos²θ)}
= √{m²g² × 1}
= mg
hence, contact force between the block and plane is mg.
also read similar questions: A body of mass 2kg rests on a rough inclined plane making an angle 30 degree with the horizontal. the coefficient of fri...
https://brainly.in/question/9045499
A block of mass 5kg is at rest on a rough inclined surface. If angle of inclination of plane is 60 then force applied by...
https://brainly.in/question/1480742
