A block of mass m is stationary on a rough inclined plane making an angle to theta
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The basic concept regarding this question is to know what is friction.
Now , Friction = coefficient of force(mew)*Normal reaction force acting upwards on the body. Here ,the weight of body is Mg acting vertically downwards. If we consider the X-Y plane on the Normal reaction ,then it will be equal to Mg cos(theta).
Therefore friction=mew* Mgcos(theta).
Thank you.
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