Question

A block of mass m moves on a horizontal surface with initial velocity v and the height of the centre of mass of the block is h from the surface consider a point a on the surface

Answer 1

Answer:

Vcom = (M*0 + m*v)/(M+m) = > mv/(M+m) m/s.

Initial velocity of block of m w.r.t Centre of Mass of system

= > v – Vcom

=> v – mv/(M+m)

=> [Mv + mv – mv]/(M+m)

=>Mv/(M+m) m/s.