Question

A block of mass 'M' moving with speed v collides with another block of mass 2m at rest . Then lighter block comes to rest after collision,the coefficient of restitution is

Answer 1

Hope this would help you.

Answer 2

Answer:

The value of coefficient of restitution is 0.5

Explanation:

Given;-

   Mass of lighter body = m

    Mass of heavier body = 2m

    Initial velocity of m = v

    Final velocity of m = 0

From the question, it is clear that the given case is of inelastic collision. Now, we know that, in an inelastic collision, for final velocity;

V₁ = (m₁ - em₂) u₁/ ( m₁ + m₂) + (1 + e) m₂u₂/ (m₁ + m₂)

where e represents coefficient of restitution.

So, putting the given values in the above formula, we obtain;-

     V = ( m - e2m ) v/ ( m + 2m)  + 0

     0 = m - e2m

     m/ 2m = e

       1/ 2 = e

   e = 0.5

Hope it helps! ;-))