A block of mass 'm' moving with velocity 'v' collides perfectly inelastically with another identical block attached to spring of force constant k. What will be the amplitude of resulting shm?
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Collision is perfectly elastic. So, after collision both bodies stick together and moves with velocity V’
So, initial linear momentum = final linear momentum
mv = ( m + m)v’
v’ = v/2
Now, potential energy stored in spring = kinetic energy after collision of bodies
⇒ 1/2 kx² = 1/2 (2m)v²/4
⇒ x² = mv²/2k
⇒x = v√(m/2k)
saurabh3025:
the collision is INelastic.... but you've solved it by considering elastic
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