Physics, asked by Manshi6967, 1 year ago

A block of mass 'm' moving with velocity 'v' collides perfectly inelastically with another identical block attached to spring of force constant k. What will be the amplitude of resulting shm?

Answers

Answered by abhi178
37

Collision is perfectly elastic. So, after collision both bodies stick together and moves with velocity V’

So, initial linear momentum = final linear momentum

mv = ( m + m)v’

v’ = v/2


Now, potential energy stored in spring = kinetic energy after collision of bodies

⇒ 1/2 kx² = 1/2 (2m)v²/4

⇒ x² = mv²/2k

⇒x = v√(m/2k)



saurabh3025: the collision is INelastic.... but you've solved it by considering elastic
abhi178: its typos. but solution is correct. I solved using inelastic collision
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