A block of mass 'm' moving with velocity 'v' collides perfectly elastically with a block of mass m which is connected to another block of same mass m through a spring of force constant k . the maximum elastic potential energy stored in the spring is
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Explanation:using law of conservation of momentum we get that : m1u1 + m2u2 = m1v1 + m2v2
Therefore the momentum in the first block is same as the second block.
KE + PE = ME therefore applying the formula of kinetic energy in terms of momentum which is (KE= P^2/2M)
Total KE is equal to total PE therefore the total potensial energy stored in the spring is P^2/2M or 1/2MV^2
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