Question

A block of mass M placed on a horizontal surface is connected to a nylon rope of mass M. A. force f 1 N is applied to the free end of the rope in the horizontal direction. The tension at the mid-point of the rope is

Answer 1

T= M + (M.A/2) whole divide by M + M.A

Answer 2

Answer:

F=ma

m=M.A

F=1N

so f= ma

1=M.A*a

a=1/M.A

T=ma

M. A*1/M.A

T=1N